World Cup 2019: India need 228 to win against SA

Southampton: India will need 228 runs to win their opening game at the on-going ICC Cricket World Cup 2019 as South Africa were bowled out at 227 for 9 at the Rose Bowl here on Wednesday.

Put to bowl first, the Indian bowlers maintained the discipline right through their innings and dominated over the Proteas in the batting friendly wicket.

Paceman Jasprit Bumrah did the early damage to South Africa taking the wickets of both openers Hasim Amla (6) and Quinton de Kock (10), reducing them to 24 for two in just 5.5 overs.

Later, the spin duo of Yuzvendra Chahal and Kuldeep Yadav were the ones who really caused the Protean wheels to come off.

Later Leg-spinner Chahal struck twice in one over, grabbing the prized scalp of skipper Faf du Plessis (38) and Rassie van der Dussen (22) to leave the Proteas in desperate trouble. He claimed four wickets in his 10 overs.

Kuldeep Yadav also chipped in with the wicket of JP Duminy, trapping the batsman lbw for three as South Africa slipped to 89 for five.

Bhubaneswar Kumar claimed two wickets in the final over of the innings.

For South Africa, Chris Morris top scored 42 of 34 balls.

As per the latest report,  India were 13/0 in five overs, while chasing the victory target. They required 215 runs from 45 overs to seal the match with 10 wickets remaining in hand.

Also Read: Dale Steyn Ruled Out Of The ICC Cricket World Cup

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